Layout of a room for growing oyster mushrooms with ventilation calculations.
These are tables for a room for growing oyster mushrooms with a load of 1 to 8 tons of substrate, in which the calculation is made:
In the figure below you can see what this table looks like.
You do not need to know the formulas for calculating ventilation, in the tables you will find ready-made answers.
All data is given in the metric system.
If your country uses a different system for measuring mass and length, you can convert my data to your usual measurement using online calculators.
Nowadays there are quite a lot of sites where data is simply converted, and you don’t need to calculate anything. You plug in the data in meters and get a figure in feet, for example.
Upon payment, you will receive tables:
The table is applicable for narrow chambers, not more than 6 meters wide.
The table is compiled in the same way as the previous one, but there is a small calculator for calculating the diameter of the nozzles-cups, depending on the length of the air ducts.
You substitute the total number of cups - the text provides step-by-step instructions on how to count them and what distance should be between the air supply nozzles. And the calculator calculates the required diameter.
To properly equip a room for growing mushrooms, you need equipment.
Therefore, instructions for calculation are attached to the tables:
The cost of two tables and instructions is $60
Send me an email veshenka.expert@gmail.com or whatsapp +380503960696 to buy.
I will send you an invoice which you can pay online via Visa and Master Card.
Here is the contents of the instruction book. I will also send you the tables that I mentioned above and a video where you can see how the evaporative panels are installed and operate.
Chapter 1 | General information about how ventilation works in the grow room | 2 |
Chapter 2 | Instructions for the selection of equipment | 5 |
Chapter 3 | Equipment placement in the ventilation system | 10 |
| 3.1. Ventilation diagram for a room with side air ducts. | 10 |
| 3.2. Possible layouts for one air duct (without side ducts) | 11 |
| 3.3. Guideline for the sequence of equipment placement in the ventilation system | 12 |
| 3.4. Recommendations for air cooling if the climate is warm and humid | 17 |
Chapter 4 | How to make air ducts | 18 |
Chapter 5 | Explanations for the ventilation calculation table | 22 |
Chapter 6 | All about block placement | 24 |
Chapter 7 | Examples of block calculations | 28 |
| 7.1. Instructions for calculating blocks in a room with one air duct | 28 |
| 7.2. Instructions for calculating blocks for a room with side air ducts. | 33 |
Chapter 8 | How to use the calculator to calculate the diameter of the cups | 39 |
To create a microclimate, we must make an interconnected system, with a climate chamber, where air flows are mixed, heated and humidified. Ventilation only distributes them evenly throughout the volume of the growing room.
In my instructions you will find all the necessary information for the competent installation of the ventilation system.
I described how to count bags in blocks and tons, if the rows are single and double, arranged in tiers.
For example, I took a growing chamber 8 by 5 meters so that you can clearly see how you can calculate the blocks for the size of your room.
I calculated by loading blocks that have a diameter of 22 cm and a weight of 9-11 kg. If you have blocks of other sizes, you can calculate them too using this method.
The instructions also have a chapter on how to place small blocks weighing up to 3 kg with side and top fruiting.
Rows can be single when they contain blocks with cuts on two opposite sides of the package.
You can place the maximum number of mushroom blocks in double rows, with one-sided perforation. Holes are cut only on one side, and the other side of the bags are located almost close to each other.
Double rows use a more compact area, but the distance between them must be greater so that the flows freely circulate between the rows of blocks.
The higher the loading of mushroom blocks per square meter, the higher the yield (in terms of unit area), and, accordingly, the income.
Therefore, it is better to equip the premises as expected at the start than to redo it later, having already lost money and time.
To accommodate 8 tons of substrate, the following area is needed:
Ceiling height | Required area, sq.m. | |
For single rows | For double rows | |
2,5 m | ≈120 | ≈90 |
3-3,5 m | 80-90 | 60-75 |
My manual says how to calculate it.